A m = 2 π r h (11b) A 0 = π (2 r h a 2 b 2) (11c) Segment of a Sphere V = π/6 h (3/4 s 2 h 2) = π h 2 (r h/3) (12a) A m = 2 π r h = π/4 (s 2 4 h 2) (12b) Sector of a Sphere V = 2/3 π r 2 h (13a)3π/2 to 2π — Fourth quadrant, so reference angle = 2π angle 10π/9 is a bit more than π, so it lies in the third quadrant In this example, the reference angle is reference angle = angle π = π/9 Answer _ π/3 sin π/6 = 1/2 ( sin π/2 sin π/6 ) Lets start from the right side of the equation 1/2 ( sin π/2 sin π/6 ) = 1/2 ( 1 1/2 ) = 1/2 1/2 = 1/4
These 27 The Maximum Value Of Sin Left Theta Frac Pi 6 Right Cos Left Theta Frac Pi 6 7 Right Attained At Theta In 0 Pi 2 1 Frac Pi 18 2 Frac Pi 6
