Integral of sec (tan^1x) / 1x² dx Okay so as we can see that derivative of tan ^1x is present in the denominator itself so Let tan ^1x = tInstead, write the integrand as $\sec x \tan x \tan^2 x \, (\color{maroon}{\sec x})^{1/2}$ and let $u=\color{maroon}{\sec x}$ Write $\tan^2 x$ in terms of $\color{maroon}{\sec x}$ and note $du$ then is $\sec x\tan x\, dx$Evaluate the following integral ∫ x 3 tan − 1 x d x Hard View solution > Evaluate the given integral ∫ x sec 2 x d x
Integration Calculus 2
